(0,100+x)(0,040+x)/(0,200-x)=5,8*10^-2

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Solution for (0,100+x)(0,040+x)/(0,200-x)=5,8*10^-2 equation: 



(0.100+x)(0.040+x)/(0.200-x)=5.8*10^-2

We move all terms to the left:

(0.100+x)(0.040+x)/(0.200-x)-(5.8*10^-2)=0



Domain of the equation: (0.200-x)!=0

We move all terms containing x to the left, all other terms to the right

-x!=-0.200

x!=-0.200/-1

x!=0.200/1

x∈R



We add all the numbers together, and all the variables

(x+0.1)(x+0.04)/(-1x+0.2)-(5.8*10^-2)=0

We add all the numbers together, and all the variables

(x+0.1)(x+0.04)/(-1x+0.2)-0.058=0

We multiply parentheses ..

(+x^2+0.04x+0.1x+0.004)/(-1x+0.2)-0.058=0

We multiply all the terms by the denominator


(+x^2+0.04x+0.1x+0.004)-(0.058)*(-1x+0.2)=0

We get rid of parentheses

x^2+0.04x+0.1x-(0.058)*(-1x+0.2)+0.004=0

We add all the numbers together, and all the variables

x^2+0.14x-(0.058)*(-1x+0.2)+0.004=0

We move all terms containing x to the left, all other terms to the right

x^2+0.14x-(0.058)*(-1x+0.2)=-0.004

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